Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

sum_(j=0)^(1)(2j-4)=

j=01(2j4)= \sum_{j=0}^{1}(2 j-4)=

Full solution

Q. j=01(2j4)= \sum_{j=0}^{1}(2 j-4)=
  1. Understanding summation notation: Understand the summation notation and define the range of the summation. The summation notation j=01(2j4)\sum_{j=0}^{1}(2j-4) means we need to evaluate the expression (2j4)(2j-4) for each integer value of jj from 00 to 11 and then sum the results.
  2. Evaluating expression for j=0j = 0: Evaluate the expression for the first value of jj, which is 00. Substitute j=0j = 0 into the expression (2j4)(2j-4). (2×04)=04=4(2\times 0 - 4) = 0 - 4 = -4
  3. Evaluating expression for j=1j = 1: Evaluate the expression for the second value of jj, which is 11. Substitute j=1j = 1 into the expression (2j4)(2j-4). (214)=24=2(2\cdot1 - 4) = 2 - 4 = -2
  4. Summing the results: Sum the results from Step 22 and Step 33.\newlineSum the values 4-4 and 2-2.\newline4+(2)=6-4 + (-2) = -6

More problems from Composition of linear and quadratic functions: find a value