Q. State all integer values of x in the interval [−8,−3] that satisfy the following inequality:4x+8≥−18Answer: x=
Solve Inequality for x: First, we need to solve the inequality 4x+8≥−18 for x.Subtract 8 from both sides of the inequality to isolate the term with x.4x+8−8≥−18−84x≥−26
Divide by 4: Next, divide both sides of the inequality by 4 to solve for x.44x≥4−26x≥−6.5
Find Integer Values: Now, we need to find all integer values of x that are greater than or equal to −6.5 and within the interval [−8,−3].The integers greater than or equal to −6.5 are −6, −5, −4, and −3.
Check Against Interval: We check these integers against the interval [−8,−3] to see which ones are included.The integers −6, −5, −4, and −3 are all within the interval [−8,−3].
Final Integer Values: Therefore, the integer values of x that satisfy the inequality 4x+8≥−18 within the interval [−8,−3] are −6, −5, −4, and −3.