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State all integer values of
x in the interval
4 <= x <= 10 that satisfy the following inequality:

-4x+6 <= -16
Answer:
x=

State all integer values of $x$ in the interval $4 \leq x \leq 10$ that satisfy the following inequality: $\newline$ $-4 x+6 \leq-16$ $\newline$ Answer: $x=$

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Solve quadratic inequalities

Full solution

Q. State all integer values of

x

in the interval

4 \leq x \leq 10

that satisfy the following inequality:

\newline

-4 x+6 \leq-16

\newline

Answer:

x=

Solve Inequality: First, we need to solve the inequality $-4x + 6 \leq -16$ for $x$ .
Subtract to Isolate x: Subtract $6$ from both sides of the inequality to isolate the term with $x$ . $\newline$ $-4x + 6 - 6 \leq -16 - 6$ $\newline$ $-4x \leq -22$
Divide to Find x: Divide both sides of the inequality by $-4$ . Remember that dividing by a negative number reverses the inequality sign. $\newline$ $-4x / -4 \geq -22 / -4$ $\newline$ $x \geq 5.5$
Find Integer Values: Now we need to find all integer values of $x$ that are greater than or equal to $5.5$ and are within the interval $4 \leq x \leq 10$ . The integers that satisfy this are $6, 7, 8, 9,$ and $10$ .

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