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State all integer values of
x in the interval
-3 <= x <= 4 that satisfy the following inequality:

3x+10 >= 4
Answer:
x=

State all integer values of $x$ in the interval $-3 \leq x \leq 4$ that satisfy the following inequality: $\newline$ $3 x+10 \geq 4$ $\newline$ Answer: $x=$

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Solve quadratic inequalities

Full solution

Q. State all integer values of

x

in the interval

-3 \leq x \leq 4

that satisfy the following inequality:

\newline

3 x+10 \geq 4

\newline

Answer:

x=

Solve Inequality for x: First, we need to solve the inequality $3x + 10 \geq 4$ for $x$ . $\newline$ Subtract $10$ from both sides of the inequality to isolate the term with $x$ . $\newline$ $3x + 10 - 10 \geq 4 - 10$ $\newline$ $3x \geq -6$
Divide by $3$ : Next, divide both sides of the inequality by $3$ to solve for $x$ . $\frac{3x}{3} \geq \frac{-6}{3}$ $x \geq -2$
Find Integer Values: Now we have the inequality $x \geq -2$ . We need to find all integer values of $x$ that satisfy this inequality within the interval $-3 \leq x \leq 4$ . $\newline$ Since $-2$ is within the interval, we start from $-2$ and list all integers up to $4$ . $\newline$ The integers are $-2$ , $-1$ , $0$ , $1$ , $x$ $0$ , $x$ $1$ , $4$ .

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