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sqrt(5^(2)-4^(2))+7(5-4)^(2)

5242+7(54)2 \sqrt{5^{2}-4^{2}}+7(5-4)^{2}

Full solution

Q. 5242+7(54)2 \sqrt{5^{2}-4^{2}}+7(5-4)^{2}
  1. Calculate Inside Square Root: We need to evaluate the expression step by step. First, we will calculate the value inside the square root, which is 52425^2 - 4^2.\newline52=255^2 = 25\newline42=164^2 = 16\newlineSo, 5242=2516=95^2 - 4^2 = 25 - 16 = 9
  2. Take Square Root: Now we take the square root of the result from the previous step. 9=3\sqrt{9} = 3
  3. Evaluate Parentheses: Next, we evaluate the second part of the expression, which is 7(54)27(5-4)^2. First, calculate the value inside the parentheses: 54=15 - 4 = 1.
  4. Raise to Power: Now we raise the result to the power of 22: 12=11^2 = 1.
  5. Multiply Result: Then we multiply the result by 77: 7×1=77 \times 1 = 7.
  6. Add Final Results: Finally, we add the results of the square root and the multiplication together to get the final answer. 3+7=103 + 7 = 10

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