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Solve the equation: 2x362x=6\sqrt{2x}-\sqrt{36}-2x=6

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Q. Solve the equation: 2x362x=6\sqrt{2x}-\sqrt{36}-2x=6
  1. Write Equation: First, let's write down the equation we need to solve: 2x362x=6\sqrt{2x} - \sqrt{36} - 2x = 6
  2. Simplify Square Root: Now, we simplify the square root of 3636, which is a perfect square and equals 66:2x62x=6\sqrt{2x} - 6 - 2x = 6
  3. Rearrange Terms: Next, we move all terms involving xx to one side of the equation and constants to the other side: 2x2x=6+6\sqrt{2x} - 2x = 6 + 6
  4. Combine Constants: We combine the constants on the right side of the equation: 2x2x=12\sqrt{2x} - 2x = 12
  5. Re-examine Equation: At this point, we have an equation that involves both xx and 2x\sqrt{2x}, which suggests we might need to square both sides to eliminate the square root. However, this will lead to a quadratic equation that might be more complex to solve. Instead, let's check if there's a simpler approach by examining the original equation for potential errors or misinterpretations.
  6. Identify Mistake: Upon re-examining the original equation, we realize that there is a mistake. The equation 2x362x=6\sqrt{2x} - \sqrt{36} - 2x = 6 cannot be true for any real value of xx because the term 2x-2x will always make the left side smaller than the right side, which is a constant 66. The square root of a number (2x\sqrt{2x}) minus that number multiplied by 22 (2x-2x) will never result in a positive number when xx is positive, and 36\sqrt{36} is a constant 66. Therefore, there is no solution to this equation.

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