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Solve using the quadratic formula.\newlines2+6s+9=0s^2 + 6s + 9 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____

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Q. Solve using the quadratic formula.\newlines2+6s+9=0s^2 + 6s + 9 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlines=s = _____ or s=s = _____
  1. Identify coefficients: Identify the coefficients of the quadratic equation s2+6s+9=0s^2 + 6s + 9 = 0. The standard form of a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0. In this case, a=1a = 1, b=6b = 6, and c=9c = 9.
  2. Recall quadratic formula: Recall the quadratic formula: s=−b±b2−4ac2as = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. We will use this formula to find the values of ss.
  3. Substitute coefficients: Substitute the coefficients aa, bb, and cc into the quadratic formula.s=−(6)±(6)2−4(1)(9)2(1)s = \frac{{-(6) \pm \sqrt{{(6)^2 - 4(1)(9)}}}}{{2(1)}}
  4. Simplify equation: Simplify the equation by calculating the discriminant b2−4acb^2 - 4ac.s=−6±36−362s = \frac{-6 \pm \sqrt{36 - 36}}{2}
  5. Calculate discriminant: Since the discriminant is 00, the square root of the discriminant is also 00. \newlines=−6±02s = \frac{-6 \pm \sqrt{0}}{2}
  6. Square root of discriminant: Simplify the equation further.\newlines=−6±02s = \frac{{-6 \pm 0}}{{2}}
  7. Simplify further: Calculate the value of ss.s=−62s = \frac{-6}{2}s=−3s = -3
  8. Calculate value of \newliness: Since the discriminant is \newline00, there is only one real solution to the equation.\newline\newlines=−3s = -3

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