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Solve using the quadratic formula.\newliner2+4r+4=0r^2 + 4r + 4 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newliner=r = _____ or r=r = _____

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Q. Solve using the quadratic formula.\newliner2+4r+4=0r^2 + 4r + 4 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newliner=r = _____ or r=r = _____
  1. Identify coefficients: Identify the coefficients of the quadratic equation r2+4r+4=0r^2 + 4r + 4 = 0. In the standard form of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the coefficients are a=1a = 1, b=4b = 4, and c=4c = 4.
  2. Recall quadratic formula: Recall the quadratic formula: r=−b±b2−4ac2ar = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. We will use this formula to find the values of rr.
  3. Substitute coefficients: Substitute the coefficients aa, bb, and cc into the quadratic formula.r=−(4)±(4)2−4(1)(4)2(1)r = \frac{{-(4) \pm \sqrt{{(4)^2 - 4(1)(4)}}}}{{2(1)}}
  4. Simplify discriminant: Simplify the expression under the square root (the discriminant). (4)2−4(1)(4)=16−16=0\sqrt{(4)^2 - 4(1)(4)} = \sqrt{16 - 16} = \sqrt{0}
  5. One real solution: Since the discriminant is 00, there is only one real solution (a repeated root).r=−4±(0)2r = \frac{-4 \pm \sqrt{(0)}}{2}
  6. Simplify further: Simplify the expression further.\newliner=−4±02r = \frac{{-4 \pm 0}}{{2}}\newliner=−42r = \frac{{-4}}{{2}}\newliner=−2r = -2

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