Solve using the quadratic formula.7x2+9x+1=0Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.x=_____ or x=_____
Q. Solve using the quadratic formula.7x2+9x+1=0Write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.x=_____ or x=_____
Identify Coefficients: To solve the quadratic equation7x2+9x+1=0 using the quadratic formula, we first need to identify the coefficients a, b, and c from the equation, where a is the coefficient of x2, b is the coefficient of x, and c is the constant term.In this equation, a=7, a0, and a1.
Quadratic Formula: The quadratic formula is given by x=2a−b±b2−4ac. We will use this formula to find the values of x.
Calculate Discriminant: First, we calculate the discriminant, which is the part under the square root in the quadratic formula: b2−4ac.Discriminant = 92−4(7)(1)=81−28=53.
Find Solutions: Since the discriminant is positive, we will have two real and distinct solutions for x. Now we will use the quadratic formula to find the two solutions for x.
First Solution: First solution using the positive square root:x=2×7−9+53x=14−9+53
Second Solution: Second solution using the negative square root:x=2×7−9−53x=14−9−53
Simplify Solutions: Now we can simplify the solutions if possible. However, since 53 cannot be simplified to a simpler radical and the fractions cannot be reduced further, we will leave the solutions in this form or convert them to decimal form rounded to the nearest hundredth.First solution as a decimal:x≈(−9+7.28)/14x≈−1.72/14$x \approx \(-0\).\(12\)
Simplify Solutions: Now we can simplify the solutions if possible. However, since \(\sqrt{53}\) cannot be simplified to a simpler radical and the fractions cannot be reduced further, we will leave the solutions in this form or convert them to decimal form rounded to the nearest hundredth.\(\newline\)First solution as a decimal:\(\newline\)\(x \approx (-9 + 7.28) / 14\)\(\newline\)\(x \approx -1.72 / 14\)\(\newline\)\(x \approx -0.12\)Second solution as a decimal:\(\newline\)\(x \approx (-9 - 7.28) / 14\)\(\newline\)\(x \approx -16.28 / 14\)\(\newline\)\(x \approx -1.16\)
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