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Solve using the quadratic formula.\newline5u2+8u1=05u^2 + 8u - 1 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlineu=u = _____ or u=u = _____

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Q. Solve using the quadratic formula.\newline5u2+8u1=05u^2 + 8u - 1 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlineu=u = _____ or u=u = _____
  1. Quadratic Formula: The quadratic formula is given by u=b±b24ac2au = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients from the quadratic equation au2+bu+c=0au^2 + bu + c = 0. In this case, a=5a = 5, b=8b = 8, and c=1c = -1.
  2. Calculate Discriminant: First, calculate the discriminant, which is the part under the square root in the quadratic formula: b24acb^2 - 4ac. Here, it is 824(5)(1)=64+20=848^2 - 4(5)(-1) = 64 + 20 = 84.
  3. Apply Quadratic Formula: Now, apply the quadratic formula with the values of aa, bb, and cc to find the two possible values for uu.\newlineu=8±842×5u = \frac{-8 \pm \sqrt{84}}{2 \times 5}\newlineu=8±8410u = \frac{-8 \pm \sqrt{84}}{10}
  4. Simplify Square Root: Simplify the square root of 8484. Since 84=4×2184 = 4 \times 21 and 4=2\sqrt{4} = 2, we can write 84\sqrt{84} as 2212\sqrt{21}.
    u=8±22110u = \frac{-8 \pm 2\sqrt{21}}{10}
  5. Split Equation: Now, split the equation into two separate equations, one for the addition and one for the subtraction. u=8+22110u = \frac{-8 + 2\sqrt{21}}{10} or u=822110u = \frac{-8 - 2\sqrt{21}}{10}
  6. Simplify Fractions: Simplify both fractions by dividing the numerator and the denominator by 22.u=4+215u = \frac{{-4 + \sqrt{21}}}{{5}} or u=4215u = \frac{{-4 - \sqrt{21}}}{{5}}
  7. Round Decimal Values: If necessary, round the decimal values to the nearest hundredth. However, since the question asks for integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth, we can leave the answers in their current form as they are already in simplest radical form.

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