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Solve using the quadratic formula.\newline2z27z+2=02z^2 - 7z + 2 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinez=z = _____ or z=z = _____

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Q. Solve using the quadratic formula.\newline2z27z+2=02z^2 - 7z + 2 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newlinez=z = _____ or z=z = _____
  1. Quadratic Formula: The quadratic formula is given by z=b±b24ac2az = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients of the quadratic equation az2+bz+c=0az^2 + bz + c = 0. For the equation 2z27z+2=02z^2 - 7z + 2 = 0, we have a=2a = 2, b=7b = -7, and c=2c = 2.
  2. Calculate Discriminant: First, calculate the discriminant, which is the part under the square root in the quadratic formula: b24acb^2 - 4ac. Here, it is (7)24(2)(2)(-7)^2 - 4(2)(2).
  3. Discriminant Calculation: Perform the calculation: (7)24(2)(2)=4916=33(-7)^2 - 4(2)(2) = 49 - 16 = 33.
  4. Apply Quadratic Formula: Now, apply the quadratic formula with the calculated discriminant. The solutions for zz will be:\newlinez=(7)±332×2z = \frac{-(-7) \pm \sqrt{33}}{2 \times 2}\newlinez=7±334z = \frac{7 \pm \sqrt{33}}{4}
  5. First Solution: We have two solutions, corresponding to the '±\pm' in the formula. The first solution is when we use the '++' sign:\newlinez=7+334z = \frac{7 + \sqrt{33}}{4}
  6. Second Solution: The second solution is when we use the '-' sign: z=7334z = \frac{7 - \sqrt{33}}{4}
  7. Decimal Approximations: These solutions cannot be simplified to integers or proper fractions. We can, however, express them as decimals rounded to the nearest hundredth. For the first solution:\newlinez(7+33)/4(7+5.74)/412.74/43.19z \approx (7 + \sqrt{33}) / 4 \approx (7 + 5.74) / 4 \approx 12.74 / 4 \approx 3.19
  8. Decimal Approximations: These solutions cannot be simplified to integers or proper fractions. We can, however, express them as decimals rounded to the nearest hundredth. For the first solution:\newlinez(7+33)/4(7+5.74)/412.74/43.19z \approx (7 + \sqrt{33}) / 4 \approx (7 + 5.74) / 4 \approx 12.74 / 4 \approx 3.19For the second solution:\newlinez(733)/4(75.74)/41.26/40.32z \approx (7 - \sqrt{33}) / 4 \approx (7 - 5.74) / 4 \approx 1.26 / 4 \approx 0.32

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