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Solve using the quadra
a) 
x^(2)=2x+1

Solve using the quadra\newlinea) x2=2x+1 x^{2}=2 x+1

Full solution

Q. Solve using the quadra\newlinea) x2=2x+1 x^{2}=2 x+1
  1. Write Standard Quadratic Form: Write the equation in standard quadratic form.\newlineTo find the roots of the equation, we need to write it in the form ax2+bx+c=0ax^2 + bx + c = 0. Subtract 2x2x and 11 from both sides to get the equation in standard form.\newlinex22x1=0x^2 - 2x - 1 = 0
  2. Identify Coefficients: Identify the coefficients aa, bb, and cc. In the equation x22x1=0x^2 - 2x - 1 = 0, the coefficients are: a=1a = 1, b=2b = -2, c=1c = -1
  3. Use Quadratic Formula: Use the quadratic formula to find the roots.\newlineThe quadratic formula is given by b±b24ac2a\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Substitute the values of aa, bb, and cc into the formula.\newline(2)±(2)241(1)21\frac{-(-2) \pm \sqrt{(-2)^2 - 4\cdot 1\cdot (-1)}}{2\cdot 1}
  4. Simplify Square Root: Simplify the expression under the square root. Calculate the discriminant b24acb^2 - 4ac. (2)241(1)=4+4=8(-2)^2 - 4\cdot 1\cdot (-1) = 4 + 4 = 8
  5. Substitute Discriminant: Substitute the discriminant back into the quadratic formula. 2±82\frac{2 \pm \sqrt{8}}{2}
  6. Divide by 22: Simplify the square root of 88. 8\sqrt{8} can be written as 4×2\sqrt{4\times2}, which simplifies to 2×22\times\sqrt{2}. (2±2×2)/2(2 \pm 2\times\sqrt{2}) / 2
  7. Write Roots in Simplest Form: Simplify the expression by dividing by 22.\newlineDivide both terms in the numerator by 22.\newline1±21 \pm \sqrt{2}
  8. Write Roots in Simplest Form: Simplify the expression by dividing by 22.\newlineDivide both terms in the numerator by 22.\newline1±21 \pm \sqrt{2}Write the roots in simplest form.\newlineThe roots of the equation are:\newlinex=1+2x = 1 + \sqrt{2} and x=12x = 1 - \sqrt{2}

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