Solve the system of equations.y=45x2−6x−20y=−6x+25Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Q. Solve the system of equations.y=45x2−6x−20y=−6x+25Write the coordinates in exact form. Simplify all fractions and radicals.(______,______)(______,______)
Set Equations Equal: We have the system of equations:y=45x2−6x−20y=−6x+25To find the intersection points, we set the two equations equal to each other.45x2−6x−20=−6x+25
Simplify Equation: Now, we simplify the equation by moving all terms to one side to set the equation to zero. 45x2−6x−20+6x−25=045x2−45=0
Combine Like Terms: Next, we simplify the equation further by combining like terms.45x2−45=045(x2−1)=0
Factorize: We recognize that x2−1 is a difference of squares, which can be factored as (x+1)(x−1). 45(x+1)(x−1)=0
Set Factors Equal: To find the values of x, we set each factor equal to zero.(x+1)=0 or (x−1)=0Solving for x gives us x=−1 and x=1.
Find Y-Values: Now that we have the x-values, we need to find the corresponding y-values by substituting x back into one of the original equations. We can use y=−6x+25 for simplicity.For x=−1: y=−6(−1)+25=6+25=31For x=1: y=−6(1)+25=−6+25=19
Coordinates: We have found the y-values corresponding to the x-values. Therefore, the coordinates of the intersection points in exact form are:First Coordinate: (−1,31)Second Coordinate: (1,19)
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