Solve the system of equations. {:[7x-3y=20],[y=5x-4],[x=◻],[y=◻]:}

Substitute Equations: Substitute the second equation into the first equation. We have the system of equations: 7x - 3y = 20 y = 5x - 4 Substitute y from the second equation into the first equation: 7x - 3(5x - 4) = 20Distribute and Combine: Distribute and combine like terms. 7x - 15x + 12 = 20 Combine like terms: -8x + 12 = 20Solve for x: Solve for x. Subtract 12 from both sides of the equation: -8x + 12 - 12 = 20 - 12 -8x = 8 Divide both sides by -8: x = 8 / -8 x = -1Substitute for y: Substitute the value of x into the second equation to solve for y. y = 5x - 4 y = 5(-1) - 4 y = -5 - 4 y = -9

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Solve the system of equations.
{:[7x-3y=20],[y=5x-4],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} 7 x-3 y=20 \\ y=5 x-4 \\ x=\square \\ y=\square \end{array}$

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Grade 8

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Q. Solve the system of equations.

\newline

\begin{array}{l} 7 x-3 y=20 \\ y=5 x-4 \\ x=\square \\ y=\square \end{array}

Substitute Equations: Substitute the second equation into the first equation. $\newline$ We have the system of equations: $\newline$ $7x - 3y = 20$ $\newline$ $y = 5x - 4$ $\newline$ Substitute $y$ from the second equation into the first equation: $\newline$ $7x - 3(5x - 4) = 20$
Distribute and Combine: Distribute and combine like terms. $\newline$ $7x - 15x + 12 = 20$ $\newline$ Combine like terms: $\newline$ $-8x + 12 = 20$
Solve for x: Solve for x. $\newline$ Subtract $12$ from both sides of the equation: $\newline$ $-8x + 12 - 12 = 20 - 12$ $\newline$ $-8x = 8$ $\newline$ Divide both sides by $-8$ : $\newline$ $x = \frac{8}{-8}$ $\newline$ $x = -1$
Substitute for y: Substitute the value of $x$ into the second equation to solve for $y$ . $\newline$ $y = 5x - 4$ $\newline$ $y = 5(-1) - 4$ $\newline$ $y = -5 - 4$ $\newline$ $y = $-9$