Solve the system of equations. {:[6x-5y=15],[x=y+3],[x=],[y=]:}

Substitute and Simplify: Step 1: Substitute the second equation into the first equation. Given: \[ 6x - 5y = 15 \] \[ x = y + 3 \] Substitute $ x = y + 3 $ into the first equation: \[ 6(y + 3) - 5y = 15 \]Solve for y: Step 2: Simplify and solve for y. \[ 6y + 18 - 5y = 15 \] \[ y + 18 = 15 \] \[ y = 15 - 18 \] \[ y = -3 \]Substitute back for x: Step 3: Substitute y back into the equation for x. \[ x = y + 3 \] \[ x = -3 + 3 \] \[ x = 0 \]

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Solve the system of equations.

{:[6x-5y=15],[x=y+3],[x=],[y=]:}

Solve the system of equations. $\newline$ $\begin{array}{l} 6 x-5 y=15 \\ x=y+3 \\ x= \\ y= \end{array}$

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Q. Solve the system of equations.

\newline

\begin{array}{l} 6 x-5 y=15 \\ x=y+3 \\ x= \\ y= \end{array}

Substitute and Simplify: Step $1$ : Substitute the second equation into the first equation. $\newline$ Given: $\newline$ $6x - 5y = 15$ $\newline$ $x = y + 3$ $\newline$ Substitute $x = y + 3$ into the first equation: $\newline$ $6(y + 3) - 5y = 15$
Solve for y: Step $2$ : Simplify and solve for y. $\newline$ $6y + 18 - 5y = 15$ $\newline$ $y + 18 = 15$ $\newline$ $y = 15 - 18$ $\newline$ $y = -3$
Substitute back for x: Step $3$ : Substitute y back into the equation for x. $\newline$ $x = y + 3$ $\newline$ $x = -3 + 3$ $\newline$ $x = 0$