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Solve the system of equations.
{:[2x+7y=3],[x=-4y],[x=◻],[y=◻]:}

Solve the system of equations.\newline2x+7y=3x=4yx=y= \begin{array}{l} 2 x+7 y=3 \\ x=-4 y \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline2x+7y=3x=4yx=y= \begin{array}{l} 2 x+7 y=3 \\ x=-4 y \\ x=\square \\ y=\square \end{array}
  1. Identify Equations: Identify the given system of equations.\newlineWe are given the following system of equations:\newline2x+7y=32x + 7y = 3\newlinex=4yx = -4y\newlineWe need to find the values of xx and yy that satisfy both equations.
  2. Substitute xx: Substitute the value of xx from the second equation into the first equation.\newlineSince x=4yx = -4y, we can replace xx in the first equation with 4y-4y:\newline2(4y)+7y=32(-4y) + 7y = 3
  3. Simplify and Solve: Simplify the equation and solve for yy.2(4y)+7y=32(-4y) + 7y = 38y+7y=3-8y + 7y = 3y=3-y = 3y=3y = -3
  4. Substitute yy for xx: Substitute the value of yy back into the second equation to find xx.
    x=4yx = -4y
    x=4(3)x = -4(-3)
    x=12x = 12