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Solve the system by substitution.

{:[9x-y=-30],[y=-x]:}

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Solve the system by substitution.\newline9xyamp;=30yamp;=x \begin{aligned} 9 x-y & =-30 \\ y & =-x \end{aligned} \newline(,) (\square, \square)

Full solution

Q. Solve the system by substitution.\newline9xy=30y=x \begin{aligned} 9 x-y & =-30 \\ y & =-x \end{aligned} \newline(,) (\square, \square)
  1. Identify Equation: Identify the equation that can be easily substituted.\newlineIn the given system of equations, the second equation y=xy = -x is already solved for yy, which makes it easy to substitute into the first equation.
  2. Substitute Expression: Substitute the expression for yy from the second equation into the first equation.\newlineSubstituting y=xy = -x into the first equation 9xy=309x - y = -30 gives us:\newline9x(x)=309x - (-x) = -30
  3. Simplify and Solve: Simplify the equation and solve for xx.9x+x=309x + x = -3010x=3010x = -30x=30/10x = -30 / 10x=3x = -3
  4. Substitute Value for y: Substitute the value of xx back into the second equation to find yy. Using y=xy = -x and x=3x = -3, we get: y=(3)y = -(-3) y=3y = 3
  5. Write Solution as Ordered Pair: Write the solution as an ordered pair.\newlineThe solution to the system of equations is (x,y)=(3,3)(x, y) = (-3, 3).