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Solve the system of equations by elimination method.\newline3x5y=7 -3x-5y=-7\newline 5x+3y=175x+3y=17

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Q. Solve the system of equations by elimination method.\newline3x5y=7 -3x-5y=-7\newline 5x+3y=175x+3y=17
  1. Write Equations: Write down the system of equations.\newlineWe have the following system of equations:\newline3x5y=7-3x - 5y = -7\newline5x+3y=175x + 3y = 17\newlineWe need to eliminate one of the variables by combining the equations.
  2. Multiply Equations: Multiply each equation by a number that will make the coefficients of one of the variables opposites.\newlineTo eliminate yy, we can multiply the first equation by 33 and the second equation by 55, which will give us coefficients of 15-15 and 1515 for yy, respectively.\newline3(3x5y)=3(7)3(-3x - 5y) = 3(-7)\newline5(5x+3y)=5(17)5(5x + 3y) = 5(17)
  3. Combine Equations: Perform the multiplication from Step 22.\newline9x15y=21-9x - 15y = -21\newline25x+15y=8525x + 15y = 85\newlineNow we can add these two equations together to eliminate yy.
  4. Add Equations: Add the two equations together to eliminate yy.(9x15y)+(25x+15y)=21+85(-9x - 15y) + (25x + 15y) = -21 + 859x+25x=64-9x + 25x = 6416x=6416x = 64
  5. Solve for x: Solve for x.\newlineDivide both sides of the equation by 1616 to find the value of x.\newline16x16=6416\frac{16x}{16} = \frac{64}{16}\newlinex=4x = 4
  6. Substitute for yy: Substitute the value of xx back into one of the original equations to solve for yy. We can use the first equation 3x5y=7-3x - 5y = -7. Substitute x=4x = 4 into the equation: 3(4)5y=7-3(4) - 5y = -7 125y=7-12 - 5y = -7
  7. Solve for y: Solve for y.\newlineAdd 1212 to both sides of the equation to isolate the term with yy.\newline5y=7+12-5y = -7 + 12\newline5y=5-5y = 5\newlineNow, divide both sides by 5-5 to find the value of yy.\newliney=5/5y = 5 / -5\newliney=1y = -1