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Solve the following system of equations by elimination.


{:[-4x-8y=-20],[8x+3y=1]:}

Solve the following system of equations by elimination.\newline4x8y=208x+3y=1 \begin{array}{c} -4 x-8 y=-20 \\ 8 x+3 y=1 \end{array}

Full solution

Q. Solve the following system of equations by elimination.\newline4x8y=208x+3y=1 \begin{array}{c} -4 x-8 y=-20 \\ 8 x+3 y=1 \end{array}
  1. Write Equations: Write down the system of equations to be solved.\newline4x8y=20-4x - 8y = -20\newline8x+3y=18x + 3y = 1\newlineWe will use the elimination method to solve this system.
  2. Multiply First Equation: Multiply the first equation by 22 so that the coefficient of xx in both equations is the same (but with opposite signs).\newline2(4x8y)=2(20)2(-4x - 8y) = 2(-20)\newline8x16y=40-8x - 16y = -40\newlineNow the system of equations is:\newline8x16y=40-8x - 16y = -40\newline8x+3y=18x + 3y = 1
  3. Add Equations: Add the two equations together to eliminate xx.(8x16y)+(8x+3y)=40+1(-8x - 16y) + (8x + 3y) = -40 + 18x+8x16y+3y=39-8x + 8x - 16y + 3y = -390x13y=390x - 13y = -39This simplifies to:13y=39-13y = -39
  4. Solve for y: Solve for y by dividing both sides of the equation by -13").\(\newline\$-13y / -13 = -39 / -13\)\(\newline\)\(y = 3\)
  5. Substitute and Solve for \(x\): Substitute \(y = 3\) into one of the original equations to solve for \(x\). We'll use the second equation.\(\newline\)\(8x + 3y = 1\)\(\newline\)\(8x + 3(3) = 1\)\(\newline\)\(8x + 9 = 1\)
  6. Subtract to Solve for x: Subtract \(9\) from both sides of the equation to solve for \(x\).\(\newline\)\[8x + 9 - 9 = 1 - 9\]\(\newline\)\[8x = -8\]
  7. Divide to Find x: Divide both sides of the equation by \(8\) to find the value of \(x\).\(\newline\)\[\frac{8x}{8} = \frac{-8}{8}\]\(\newline\)\(x = -1\)