Q. Solve the following system of equations by elimination.−4x−8y=−208x+3y=1
Write Equations: Write down the system of equations to be solved.−4x−8y=−208x+3y=1We will use the elimination method to solve this system.
Multiply First Equation: Multiply the first equation by 2 so that the coefficient of x in both equations is the same (but with opposite signs).2(−4x−8y)=2(−20)−8x−16y=−40Now the system of equations is:−8x−16y=−408x+3y=1
Add Equations: Add the two equations together to eliminate x.(−8x−16y)+(8x+3y)=−40+1−8x+8x−16y+3y=−390x−13y=−39This simplifies to:−13y=−39
Solve for y: Solve for y by dividing both sides of the equation by -13").\(\newline\$-13y / -13 = -39 / -13\)\(\newline\)\(y = 3\)
Substitute and Solve for \(x\): Substitute \(y = 3\) into one of the original equations to solve for \(x\). We'll use the second equation.\(\newline\)\(8x + 3y = 1\)\(\newline\)\(8x + 3(3) = 1\)\(\newline\)\(8x + 9 = 1\)
Subtract to Solve for x: Subtract \(9\) from both sides of the equation to solve for \(x\).\(\newline\)\[8x + 9 - 9 = 1 - 9\]\(\newline\)\[8x = -8\]
Divide to Find x: Divide both sides of the equation by \(8\) to find the value of \(x\).\(\newline\)\[\frac{8x}{8} = \frac{-8}{8}\]\(\newline\)\(x = -1\)