Solve the following system of equations. {:[-5x+4y=3],[quad x=2y-15],[x=],[y=]:}

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Solve the following system of equations.  {:[-5x+4y=3],[quad x=2y-15],[x=],[y=]:}

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Write Equations: First, let's write down the system of equations we need to solve: -5x + 4y = 3 x = 2y - 15 We will use the substitution method to solve this system. Since the second equation gives us x in terms of y, we can substitute x in the first equation with the expression from the second equation.Substitute x: Substitute x = 2y - 15 into the first equation: -5(2y - 15) + 4y = 3 Now, distribute the -5 into the parentheses: -10y + 75 + 4y = 3Combine Terms: Combine like terms: -10y + 4y + 75 = 3 -6y + 75 = 3 Now, we will isolate y by moving 75 to the other side of the equation: -6y = 3 - 75Isolate y: Calculate the right side of the equation: -6y = -72 Now, divide both sides by -6 to solve for y: y = -72 / -6 y = 12Calculate y: Now that we have the value of y, we can substitute it back into the second equation to find x: x = 2y - 15 x = 2(12) - 15Substitute y: Calculate the value of x: x = 24 - 15 x = 9

Solve the following system of equations. $\newline$ $\begin{array}{l} -5 x+4 y=3 \\ \quad x=2 y-15 \\ x= \\ y= \end{array}$

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Solve the following system of equations.\newline−5x+4y=3x=2y−15x=y= \begin{array}{l} -5 x+4 y=3 \\ \quad x=2 y-15 \\ x= \\ y= \end{array} −5x+4y=3x=2y−15x=y=​

Solve the following system of equations. $\newline$ $\begin{array}{l} -5 x+4 y=3 \\ \quad x=2 y-15 \\ x= \\ y= \end{array}$