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Solve the following logarithm problem for the positive solution for 
x.

log_(27)x=-(2)/(3)
Answer:

Solve the following logarithm problem for the positive solution for x x .\newlinelog27x=23 \log _{27} x=-\frac{2}{3} \newlineAnswer:

Full solution

Q. Solve the following logarithm problem for the positive solution for x x .\newlinelog27x=23 \log _{27} x=-\frac{2}{3} \newlineAnswer:
  1. Understand the logarithmic equation: Understand the logarithmic equation.\newlineWe have the equation log27(x)=23\log_{27}(x) = -\frac{2}{3}. We need to find the value of xx that satisfies this equation.
  2. Convert to exponential form: Convert the logarithmic form to exponential form.\newlineThe logarithmic equation log27x\log_{27} x can be rewritten in exponential form as 27log27(x)=x27^{\log_{27}(x)} = x. Using the given equation, we have 27(23)=x27^{-\left(\frac{2}{3}\right)} = x.
  3. Calculate value of 27(2/3)27^{(-2/3)}: Calculate the value of 2727 raised to the power of negative two-thirds.\newlineSince 2727 is 333^3, we can rewrite 27(23)27^{(-\frac{2}{3})} as (33)(23)(3^3)^{(-\frac{2}{3})}. By the power of a power rule, this simplifies to 323^{-2}, which is 132\frac{1}{3^2} or 19\frac{1}{9}.
  4. Verify the solution: Verify the solution.\newlineWe found that x=19x = \frac{1}{9}. To verify, we can plug this value back into the original equation and check if it holds true: log27(19)=23\log_{27}(\frac{1}{9}) = -\frac{2}{3}. Since 19\frac{1}{9} is 323^{-2} and 2727 is 333^3, the logarithm simplifies to 23-\frac{2}{3}, which matches the right side of the equation.

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