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Solve the following logarithm problem for the positive solution for 
x.

log_(x)343=(3)/(2)
Answer:

Solve the following logarithm problem for the positive solution for x x .\newlinelogx343=32 \log _{x} 343=\frac{3}{2} \newlineAnswer:

Full solution

Q. Solve the following logarithm problem for the positive solution for x x .\newlinelogx343=32 \log _{x} 343=\frac{3}{2} \newlineAnswer:
  1. Understand the logarithmic equation: Understand the logarithmic equation.\newlineThe given logarithmic equation is logx343=32\log_{x}343=\frac{3}{2}, which means that xx raised to the power of 32\frac{3}{2} equals 343343.
  2. Convert to exponential form: Convert the logarithmic equation to exponential form.\newlineUsing the definition of a logarithm, we can rewrite the equation as x32=343x^{\frac{3}{2}} = 343.
  3. Find base of exponent: Find the base of the exponent that results in 343343. We know that 73=3437^3 = 343, so we can rewrite 343343 as 737^3.
  4. Set bases equal: Set the expression with the base xx equal to the expression with base 77. Now we have x3/2=73x^{3/2} = 7^3. Since the exponents are equal, we can set the bases equal to each other.
  5. Solve for x: Solve for x.\newlineTo find xx, we need to find a number that when raised to the power of (3)/(2)(3)/(2) gives 737^3. We can take the cube root of both sides and then square it to isolate xx.\newline(x(3/2))(2/3)=(73)(2/3)(x^{(3/2)})^{(2/3)} = (7^3)^{(2/3)}\newlinex=72x = 7^2\newlinex=49x = 49

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