Solve the following for y:(x)/(6)+(y)/(4)=1 y=

Clear Fractions: Multiply every term by the least common multiple of the denominators to clear the fractions. The least common multiple of 6 and 4 is 12. Multiply each term by 12 to clear the fractions. (12 * (x)/(6)) + (12 * (y)/(4)) = 12 * 1Simplify Terms: Simplify each term. (12/6) * x + (12/4) * y = 12 2x + 3y = 12Isolate Variable y: Isolate the variable y. To isolate y, subtract 2x from both sides of the equation. 2x + 3y - 2x = 12 - 2x 3y = 12 - 2xSolve for y: Divide both sides by 3 to solve for y. 3y / 3 = (12 - 2x) / 3 y = (12 - 2x) / 3

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Math Problems

Grade 8

Solve equations with the distributive property

Full solution

Q. Solve the following for

y

\frac{x}{6}+\frac{y}{4}=1

\newline

y=

Clear Fractions: Multiply every term by the least common multiple of the denominators to clear the fractions. $\newline$ The least common multiple of $6$ and $4$ is $12$ . Multiply each term by $12$ to clear the fractions. $\newline$ $(12 \times \frac{x}{6}) + (12 \times \frac{y}{4}) = 12 \times 1$
Simplify Terms: Simplify each term. $\newline$ $(\frac{12}{6}) \times x + (\frac{12}{4}) \times y = 12$ $\newline$ $2x + 3y = 12$
Isolate Variable $y$ : Isolate the variable $y$ . $\newline$ To isolate $y$ , subtract $2x$ from both sides of the equation. $\newline$ $2x + 3y - 2x = 12 - 2x$ $\newline$ $3y = 12 - 2x$
Solve for y: Divide both sides by $3$ to solve for y. $\frac{3y}{3} = \frac{(12 - 2x)}{3}$ $y = \frac{(12 - 2x)}{3}$