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Solve the exponential equation for 
x.

{:[((9)/(8))^(3x+12)=1],[x=]:}

Solve the exponential equation for x x .\newline(98)3x+12=1x= \begin{array}{l} \left(\frac{9}{8}\right)^{3 x+12}=1 \\ x=\square \end{array}

Full solution

Q. Solve the exponential equation for x x .\newline(98)3x+12=1x= \begin{array}{l} \left(\frac{9}{8}\right)^{3 x+12}=1 \\ x=\square \end{array}
  1. Identify given equation: Identify the given exponential equation and the value it is equal to.\newlineThe given equation is (98)3x+12=1\left(\frac{9}{8}\right)^{3x+12} = 1. We need to find the value of xx that satisfies this equation.
  2. Recognize power property: Recognize that any non-zero number raised to the power of 00 is 11. Since (98)3x+12=1\left(\frac{9}{8}\right)^{3x+12} = 1, we can deduce that the exponent 3x+123x+12 must be equal to 00 because 98\frac{9}{8} is a non-zero number.
  3. Set exponent equal: Set the exponent equal to 00 and solve for xx. \newline3x+12=03x + 12 = 0\newlineSubtract 1212 from both sides of the equation to isolate the term with xx.\newline3x+1212=0123x + 12 - 12 = 0 - 12\newline3x=123x = -12
  4. Divide and solve for x: Divide both sides of the equation by 33 to solve for x.\newline3x3=123\frac{3x}{3} = \frac{-12}{3}\newlinex=4x = -4

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