Solve the equation x^(2)-x-11=-2x to the nearest tenth. Answer: x=

Simplify the equation: First, we need to simplify the equation by moving all terms to one side to set the equation to zero. x^(2) - x - 11 = -2x Add 2x to both sides to combine like terms. x^(2) - x + 2x - 11 = 0 x^(2) + x - 11 = 0Quadratic formula setup: Now, we have a quadratic equation in the form ax^2 + bx + c = 0. We can solve for x using the quadratic formula, x = [-b ± sqrt(b^2 - 4ac)] / (2a), where a = 1, b = 1, and c = -11. First, calculate the discriminant (b^2 - 4ac). Discriminant = (1)^2 - 4(1)(-11) Discriminant = 1 + 44 Discriminant = 45Calculate discriminant: Since the discriminant is positive, we have two real solutions. Now, we will use the quadratic formula to find the solutions. x = [-1 ± sqrt(45)] / (2*1) x = [-1 ± sqrt(45)] / 2Use quadratic formula: Calculate the two solutions using the quadratic formula. First solution: x = (-1 + sqrt(45)) / 2 x = (-1 + 6.708) / 2 x = 5.708 / 2 x = 2.854 Round to the nearest tenth: x ≈ 2.9 Second solution: x = (-1 - sqrt(45)) / 2 x = (-1 - 6.708) / 2 x = -7.708 / 2 x = -3.854 Round to the nearest tenth: x ≈ -3.9

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Solve the equation
x^(2)-x-11=-2x to the nearest tenth.
Answer:
x=

Solve the equation $x^{2}-x-11=-2 x$ to the nearest tenth. $\newline$ Answer: $x=$

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Q. Solve the equation

x^{2}-x-11=-2 x

to the nearest tenth.

\newline

Answer:

x=

Simplify the equation: First, we need to simplify the equation by moving all terms to one side to set the equation to zero. $\newline$ $x^{2} - x - 11 = -2x$ $\newline$ Add $2x$ to both sides to combine like terms. $\newline$ $x^{2} - x + 2x - 11 = 0$ $\newline$ $x^{2} + x - 11 = 0$
Quadratic formula setup: Now, we have a quadratic equation in the form $ax^2 + bx + c = 0$ . We can solve for $x$ using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ , where $a = 1$ , $b = 1$ , and $c = -11$ . First, calculate the discriminant $(b^2 - 4ac)$ . Discriminant = $(1)^2 - 4(1)(-11)$ Discriminant = $1 + 44$ Discriminant = $45$
Calculate discriminant: Since the discriminant is positive, we have two real solutions. Now, we will use the quadratic formula to find the solutions. $\newline$ $x = \frac{-1 \pm \sqrt{45}}{2\cdot1}$ $\newline$ $x = \frac{-1 \pm \sqrt{45}}{2}$
Use quadratic formula: Calculate the two solutions using the quadratic formula. $\newline$ First solution: $\newline$ $x = \frac{-1 + \sqrt{45}}{2}$ $\newline$ $x = \frac{-1 + 6.708}{2}$ $\newline$ $x = \frac{5.708}{2}$ $\newline$ $x = 2.854$ $\newline$ Round to the nearest tenth: $x \approx 2.9$ $\newline$ Second solution: $\newline$ $x = \frac{-1 - \sqrt{45}}{2}$ $\newline$ $x = \frac{-1 - 6.708}{2}$ $\newline$ $x = \frac{-7.708}{2}$ $\newline$ $x = -3.854$ $\newline$ Round to the nearest tenth: $x \approx -3.9$