Solve the equation x^(2)+17 x+45=0 to the nearest tenth. Answer: x=

Identify the quadratic equation: Identify the quadratic equation. The given equation is x^2 + 17x + 45 = 0, which is a quadratic equation in the standard form ax^2 + bx + c = 0, where a = 1, b = 17, and c = 45.Apply the quadratic formula: Apply the quadratic formula to find the solutions for x. The quadratic formula is x = [-b ± sqrt(b^2 - 4ac)] / (2a). For our equation, a = 1, b = 17, and c = 45.Calculate the discriminant: Calculate the discriminant (b^2 - 4ac). Discriminant = b^2 - 4ac = (17)^2 - 4(1)(45) = 289 - 180 = 109.Calculate the two solutions: Calculate the two solutions using the quadratic formula. x = [-b ± sqrt(discriminant)] / (2a) x = [-17 ± sqrt(109)] / 2Calculate the first solution: Calculate the first solution (using the '+' in '±'). x1 = (-17 + sqrt(109)) / 2 x1 ≈ (-17 + 10.4403) / 2 x1 ≈ -6.5597 / 2 x1 ≈ -3.27985 Round to the nearest tenth: x1 ≈ -3.3Calculate the second solution: Calculate the second solution (using the '-' in '±'). x2 = (-17 - sqrt(109)) / 2 x2 ≈ (-17 - 10.4403) / 2 x2 ≈ -27.4403 / 2 x2 ≈ -13.72015 Round to the nearest tenth: x2 ≈ -13.7

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Solve the equation
x^(2)+17 x+45=0 to the nearest tenth.
Answer:
x=

Solve the equation $x^{2}+17 x+45=0$ to the nearest tenth. $\newline$ Answer: $x=$

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Algebra 2

Solve exponential equations using common logarithms

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Q. Solve the equation

x^{2}+17 x+45=0

to the nearest tenth.

\newline

Answer:

x=

Identify the quadratic equation: Identify the quadratic equation. $\newline$ The given equation is $x^2 + 17x + 45 = 0$ , which is a quadratic equation in the standard form $ax^2 + bx + c = 0$ , where $a = 1$ , $b = 17$ , and $c = 45$ .
Apply the quadratic formula: Apply the quadratic formula to find the solutions for $x$ . The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ . For our equation, $a = 1$ , $b = 17$ , and $c = 45$ .
Calculate the discriminant: Calculate the discriminant $b^2 - 4ac$ . $\newline$ Discriminant = $b^2 - 4ac = (17)^2 - 4(1)(45) = 289 - 180 = 109$ .
Calculate the two solutions: Calculate the two solutions using the quadratic formula. $\newline$ $x = \frac{-b \pm \sqrt{\text{discriminant}}}{2a}$ $\newline$ $x = \frac{-17 \pm \sqrt{109}}{2}$
Calculate the first solution: Calculate the first solution (using the '+' in ' $\pm$ '). $\newline$ $x_1 = \frac{-17 + \sqrt{109}}{2}$ $\newline$ $x_1 \approx \frac{-17 + 10.4403}{2}$ $\newline$ $x_1 \approx \frac{-6.5597}{2}$ $\newline$ $x_1 \approx -3.27985$ $\newline$ Round to the nearest tenth: $x_1 \approx -3.3$
Calculate the second solution: Calculate the second solution (using the '-' in ' $\pm$ '). $\newline$ $x_2 = \frac{{-17 - \sqrt{109}}}{{2}}$ $\newline$ $x_2 \approx \frac{{-17 - 10.4403}}{{2}}$ $\newline$ $x_2 \approx \frac{{-27.4403}}{{2}}$ $\newline$ $x_2 \approx -13.72015$ $\newline$ Round to the nearest tenth: $x_2 \approx -13.7$