Solve the equation. {:[(w)/(5)=3],[w=◻]:}

Identify Equation: Identify the first equation in the system. The first equation is (w/5) = 3. To solve for w, we need to isolate w on one side of the equation.Multiply by 5: Multiply both sides of the first equation by 5 to solve for w. (w/5) * 5 = 3 * 5 w = 15 We have found the value of w from the first equation.Check Second Equation: Check the second equation in the system to see if the value of w satisfies it. The second equation is w = ◻, which means we need to check if the value we found for w, which is 15, can be placed in the box. Since there is only one equation with w and no other conditions, the value of w we found from the first equation is the solution to the system.

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Solve the equation.

{:[(w)/(5)=3],[w=◻]:}

Solve the equation. $\newline$ \begin{align} \frac{w}{5} &= 3,\ w &= \Box \end{align}

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Q. Solve the equation.

\newline

\begin{align*} \frac{w}{5} &= 3,\ w &= \Box \end{align*}

Identify Equation: Identify the first equation in the system. $\newline$ The first equation is $(\frac{w}{5}) = 3$ . $\newline$ To solve for $w$ , we need to isolate $w$ on one side of the equation.
Multiply by $5$ : Multiply both sides of the first equation by $5$ to solve for $w$ . $\frac{w}{5} \times 5 = 3 \times 5$ $w = 15$ We have found the value of $w$ from the first equation.
Check Second Equation: Check the second equation in the system to see if the value of $w$ satisfies it. $\newline$ The second equation is $w = \square$ , which means we need to check if the value we found for $w$ , which is $15$ , can be placed in the box. $\newline$ Since there is only one equation with $w$ and no other conditions, the value of $w$ we found from the first equation is the solution to the system.