Solve the equation by factoring: x^(3)-8x^(2)-9x=0 Answer: x=

Factor GCF: Factor out the greatest common factor (GCF) from the equation x^3 - 8x^2 - 9x = 0. The GCF is x, so we factor it out to get x(x^2 - 8x - 9) = 0.Factor Quadratic Equation: Now we need to factor the quadratic equation x^2 - 8x - 9. We look for two numbers that multiply to -9 and add up to -8. The numbers are -9 and +1. So we can write the quadratic as (x - 9)(x + 1).Find Roots: Now we have the factored form of the equation: x(x - 9)(x + 1) = 0. To find the roots, we set each factor equal to zero and solve for x.First Root: Set the first factor equal to zero: x = 0. This gives us the first root.Second Root: Set the second factor equal to zero: x - 9 = 0. Solving for x gives us x = 9, which is the second root.Third Root: Set the third factor equal to zero: x + 1 = 0. Solving for x gives us x = -1, which is the third root.

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Solve the equation by factoring:

x^(3)-8x^(2)-9x=0
Answer:
x=

Solve the equation by factoring: $\newline$ $x^{3}-8 x^{2}-9 x=0$ $\newline$ Answer: $x=$

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Algebra 2

Quadratic equation with complex roots

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Q. Solve the equation by factoring:

\newline

x^{3}-8 x^{2}-9 x=0

\newline

Answer:

x=

Factor GCF: Factor out the greatest common factor (GCF) from the equation $x^3 - 8x^2 - 9x = 0$ . The GCF is $x$ , so we factor it out to get $x(x^2 - 8x - 9) = 0$ .
Factor Quadratic Equation: Now we need to factor the quadratic equation $x^2 - 8x - 9$ . We look for two numbers that multiply to $-9$ and add up to $-8$ . The numbers are $-9$ and $+1$ . So we can write the quadratic as $(x - 9)(x + 1)$ .
Find Roots: Now we have the factored form of the equation: $x(x - 9)(x + 1) = 0$ . To find the roots, we set each factor equal to zero and solve for $x$ .
First Root: Set the first factor equal to zero: $x = 0$ . This gives us the first root.
Second Root: Set the second factor equal to zero: $x - 9 = 0$ . Solving for $x$ gives us $x = 9$ , which is the second root.
Third Root: Set the third factor equal to zero: $x + 1 = 0$ . Solving for $x$ gives us $x = -1$ , which is the third root.