Solve the equation by factoring: 8x+7x^(2)-x^(3)=0 Answer: x=

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Solve the equation by factoring:  8x+7x^(2)-x^(3)=0 Answer:  x=

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Rewrite in standard form: Rewrite the equation in standard form. The standard form of a polynomial is to have the terms in descending order of their exponents. The given equation is already in standard form: -x^3 + 7x^2 + 8x = 0.Factor out common factor: Factor out the greatest common factor. The greatest common factor in each term is x. Factor x out of the equation: x(-x^2 + 7x + 8) = 0.Factor the quadratic: Factor the quadratic equation. Now we need to factor the quadratic equation -x^2 + 7x + 8. We are looking for two numbers that multiply to -8 (a*c) and add up to 7 (b). These numbers are -1 and 8. So we can write the quadratic as (-x + 8)(x + 1).Write factored form: Write the factored form of the original equation. Now that we have factored the quadratic, we can write the entire factored form of the original equation as x(-x + 8)(x + 1) = 0.Set equal and solve: Set each factor equal to zero and solve for x. We have three factors: x, -x + 8, and x + 1. Setting each factor equal to zero gives us the equations x = 0, -x + 8 = 0, and x + 1 = 0.Solve for x: Solve each equation for x. Solving x = 0 gives us the root x = 0. Solving -x + 8 = 0 gives us x = 8. Solving x + 1 = 0 gives us x = -1.Write roots: Write the roots in simplest form. The roots of the equation are x = 0, x = 8, and x = -1.

Solve the equation by factoring: $\newline$ $8 x+7 x^{2}-x^{3}=0$ $\newline$ Answer: $x=$

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Solve the equation by factoring:\newline8x+7x2−x3=0 8 x+7 x^{2}-x^{3}=0 8x+7x2−x3=0\newlineAnswer: x= x= x=

Solve the equation by factoring: $\newline$ $8 x+7 x^{2}-x^{3}=0$ $\newline$ Answer: $x=$