Solve the equation by factoring: 36x^(2)-160 x-2x^(3)=0 Answer: x=

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Solve the equation by factoring:  36x^(2)-160 x-2x^(3)=0 Answer:  x=

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Rewrite in Standard Form: First, let's rewrite the equation in standard form by arranging the terms in descending order of their exponents. The given equation is 36x^2 - 160x - 2x^3 = 0. Rearrange the terms to get -2x^3 + 36x^2 - 160x = 0.Factor Out GCF: Next, we factor out the greatest common factor (GCF) from all the terms. The GCF in this case is -2x. So, we factor -2x out of each term to get -2x(x^2 - 18x + 80) = 0.Factor Quadratic Expression: Now, we need to factor the quadratic expression inside the parentheses. We are looking for two numbers that multiply to 80 and add up to -18. The numbers that satisfy these conditions are -10 and -8. So, we can write the quadratic as (x - 10)(x - 8).Find Roots: The factored form of the equation is now -2x(x - 10)(x - 8) = 0. To find the roots, we set each factor equal to zero and solve for x.First Factor: Setting the first factor equal to zero gives us -2x = 0, which means x = 0.Second Factor: Setting the second factor equal to zero gives us x - 10 = 0, which means x = 10.Third Factor: Setting the third factor equal to zero gives us x - 8 = 0, which means x = 8.

Solve the equation by factoring: $\newline$ $36 x^{2}-160 x-2 x^{3}=0$ $\newline$ Answer: $x=$

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Solve the equation by factoring:\newline36x2−160x−2x3=0 36 x^{2}-160 x-2 x^{3}=0 36x2−160x−2x3=0\newlineAnswer: x= x= x=

Solve the equation by factoring: $\newline$ $36 x^{2}-160 x-2 x^{3}=0$ $\newline$ Answer: $x=$