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Solve the equation: (78z211z)+(15z+1312z2)=20z2+bz+20(7-8z^2-11z)+(15z+13-12z^2)=-20z^2+bz+20

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Q. Solve the equation: (78z211z)+(15z+1312z2)=20z2+bz+20(7-8z^2-11z)+(15z+13-12z^2)=-20z^2+bz+20
  1. Combine like terms: Combine like terms on the left side of the equation.\newline(7 - 8z^2 - 11z) + (15z + 13 - 12z^2) \(\newline= 7 - 8z^2 - 11z + 15z + 13 - 12z^2\newline= 7 + 13 - 8z^2 - 12z^2 - 11z + 15z\newline= 20 - 20z^2 + 4z\)
  2. Set equal to right side: Now we have the simplified left side of the equation, which is 2020z2+4z20 - 20z^2 + 4z. We set this equal to the right side of the equation.\newline2020z2+4z=20z2+bz+2020 - 20z^2 + 4z = -20z^2 + bz + 20
  3. Find value of \newlinebb: Since the equation is already simplified, we can compare the coefficients of the corresponding terms on both sides of the equation to find the value of \newlinebb.\newlineThe coefficient of \newlinezz on the left side is \newline44, so \newlinebb must be \newline44.
  4. Check coefficients and constants: Check if the constant terms and the coefficients of z2z^2 are equal on both sides.\newlineLeft side: constant term is 2020, coefficient of z2z^2 is 20-20.\newlineRight side: constant term is 2020, coefficient of z2z^2 is 20-20.\newlineBoth sides match, so the equation is balanced.

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