Solve the equation 2x^(2)+8x-10=-3x^(2) to the nearest tenth. Answer: x=

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Solve the equation  2x^(2)+8x-10=-3x^(2) to the nearest tenth. Answer:  x=

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Move Terms to One Side: First, we need to move all terms to one side of the equation to set it equal to zero. We do this by adding 3x^2 to both sides of the equation. 2x^2 + 8x - 10 + 3x^2 = -3x^2 + 3x^2 This simplifies to: 5x^2 + 8x - 10 = 0Solve Quadratic Equation: Next, we need to solve the quadratic equation. We can do this by using the quadratic formula, which is x = (-b ± √(b^2 - 4ac)) / (2a), where a = 5, b = 8, and c = -10.Calculate Discriminant: Now we calculate the discriminant, which is the part under the square root in the quadratic formula: b^2 - 4ac. Discriminant = 8^2 - 4(5)(-10) Discriminant = 64 + 200 Discriminant = 264Find Real Solutions: Since the discriminant is positive, we have two real solutions. We will use the quadratic formula to find both. x = (-8 ± √264) / (2 * 5) x = (-8 ± √264) / 10Simplify Square Root: We simplify the square root of 264 to get an approximate decimal value for the square root. √264 ≈ 16.2 (rounded to one decimal place)Substitute and Solve: Now we substitute the approximate value of the square root back into the quadratic formula to find the two solutions. x = (-8 + 16.2) / 10 and x = (-8 - 16.2) / 10 x ≈ 0.82 and x ≈ -2.42 (rounded to the nearest tenth)

Solve the equation $2 x^{2}+8 x-10=-3 x^{2}$ to the nearest tenth. $\newline$ Answer: $x=$

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Solve the equation 2x2+8x−10=−3x2 2 x^{2}+8 x-10=-3 x^{2} 2x2+8x−10=−3x2 to the nearest tenth.\newlineAnswer: x= x= x=

Solve the equation $2 x^{2}+8 x-10=-3 x^{2}$ to the nearest tenth. $\newline$ Answer: $x=$