Solve the equation 2x^(2)+16 x+56=x^(2) to the nearest tenth. Answer: x=

Set Equation to Zero: First, we need to set the equation to zero by moving all terms to one side. Subtract x^2 from both sides of the equation. 2x^2 + 16x + 56 - x^2 = x^2 - x^2 This simplifies to: x^2 + 16x + 56 = 0Factor or Use Formula: Next, we need to factor the quadratic equation if possible, or use the quadratic formula to find the values of x. The quadratic equation is x^2 + 16x + 56 = 0. Let's try to factor it. We are looking for two numbers that multiply to 56 and add up to 16. The numbers 8 and 7 fit this requirement. So we can write the equation as: (x + 8)(x + 7) = 0Apply Zero Product Property: Now, we apply the zero product property, which states that if a product of two factors is zero, then at least one of the factors must be zero. So we set each factor equal to zero and solve for x: x + 8 = 0 or x + 7 = 0Solve for x: Solve the first equation for x: x + 8 = 0 x = -8Solve for x: Solve the second equation for x: x + 7 = 0 x = -7Final Solutions: We have found two solutions for x. They are x = -8 and x = -7. Since we are asked to round to the nearest tenth, the solutions remain the same as they are already integers.

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Solve the equation
2x^(2)+16 x+56=x^(2) to the nearest tenth.
Answer:
x=

Solve the equation $2 x^{2}+16 x+56=x^{2}$ to the nearest tenth. $\newline$ Answer: $x=$

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Full solution

Q. Solve the equation

2 x^{2}+16 x+56=x^{2}

to the nearest tenth.

\newline

Answer:

x=

Set Equation to Zero: First, we need to set the equation to zero by moving all terms to one side. $\newline$ Subtract $x^2$ from both sides of the equation. $\newline$ $2x^2 + 16x + 56 - x^2 = x^2 - x^2$ $\newline$ This simplifies to: $\newline$ $x^2 + 16x + 56 = 0$
Factor or Use Formula: Next, we need to factor the quadratic equation if possible, or use the quadratic formula to find the values of $x$ . The quadratic equation is $x^2 + 16x + 56 = 0$ . Let's try to factor it. We are looking for two numbers that multiply to $56$ and add up to $16$ . The numbers $8$ and $7$ fit this requirement. So we can write the equation as: $(x + 8)(x + 7) = 0$
Apply Zero Product Property: Now, we apply the zero product property, which states that if a product of two factors is zero, then at least one of the factors must be zero. $\newline$ So we set each factor equal to zero and solve for $x$ : $\newline$ $x + 8 = 0$ or $x + 7 = 0$
Solve for x: Solve the first equation for x: $\newline$ $x + 8 = 0$ $\newline$ $x = -8$
Solve for x: Solve the second equation for x: $\newline$ $x + 7 = 0$ $\newline$ $x = -7$
Final Solutions: We have found two solutions for $x$ . They are $x = -8$ and $x = -7$ . Since we are asked to round to the nearest tenth, the solutions remain the same as they are already integers.