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Solve the equation.\newline23pamp;=5pamp;=\begin{align*} \frac{2}{3}p &= 5\\ p &= \Box \end{align*}

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Q. Solve the equation.\newline23p=5p=\begin{align*} \frac{2}{3}p &= 5\\ p &= \Box \end{align*}
  1. Analyze Equations: Analyze the given system of equations.\newlineWe have a system of two equations:\newline11) (23)p=5(\frac{2}{3})p = 5\newline22) p=p = \square\newlineWe need to find the value of pp that satisfies both equations.
  2. Solve First Equation: Solve the first equation for pp. To find the value of pp from the first equation, we multiply both sides by the reciprocal of (2/3)(2/3), which is (3/2)(3/2). (2/3)p×(3/2)=5×(3/2)(2/3)p \times (3/2) = 5 \times (3/2) p=15/2p = 15/2
  3. Substitute into Second Equation: Substitute the value of pp into the second equation.\newlineSince the second equation is simply p=p = \square, we place the value we found for pp into the box.\newlinep=152p = \frac{15}{2}