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Solve for zz.\newline3(z + 8) > 6

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Full solution

Q. Solve for zz.\newline3(z+8)>63(z + 8) > 6
  1. Distribute 33 into parentheses: question_prompt: Solve for zz in the inequality 3(z + 8) > 6.
  2. Combine like terms: First, distribute the 33 into the parentheses: 3 \times z + 3 \times 8 > 6.
  3. Subtract 2424 from both sides: That gives us 3z + 24 > 6.
  4. Isolate the z term: Next, subtract 2424 from both sides to isolate the z term: 3z + 24 - 24 > 6 - 24.
  5. Divide by 33 to solve for z: Now we have 3z > -18.
  6. Divide by 33 to solve for z: Now we have 3z > -18. Finally, divide both sides by 33 to solve for z: \frac{3z}{3} > \frac{-18}{3}.

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