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Solve for zz.\newline3(z + 19) > 12

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Full solution

Q. Solve for zz.\newline3(z+19)>123(z + 19) > 12
  1. Distribute 33: First, we need to distribute the 33 across the terms inside the parentheses.\newlineCalculation: 3(z + 19) > 12 becomes 3z + 3\times19 > 12.\newlineMath error check:
  2. Simplify Right Side: Next, we simplify the right side of the inequality by multiplying 33 by 1919.\newlineCalculation: 3z + 57 > 12.\newlineMath error check:
  3. Isolate Variable Term: Now, we isolate the variable term 3z3z by subtracting 5757 from both sides of the inequality.\newlineCalculation: 3z + 57 - 57 > 12 - 57, which simplifies to 3z > -45.\newlineMath error check:
  4. Solve for z: Finally, we solve for z by dividing both sides of the inequality by 33. \newlineCalculation: \frac{3z}{3} > \frac{-45}{3}, which simplifies to z > -15. \newlineMath error check:

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