Solve for z. (3)/(4)z+8=68 Answer: z=

Subtract 8: Subtract 8 from both sides of the equation to isolate the term containing z. (3/4)z + 8 - 8 = 68 - 8 This simplifies to: (3/4)z = 60Multiply by reciprocal: Multiply both sides of the equation by the reciprocal of (3/4) to solve for z. The reciprocal of (3/4) is (4/3). So we multiply both sides by (4/3): (4/3) * (3/4)z = 60 * (4/3) This simplifies to: z = 60 * (4/3)Perform multiplication: Perform the multiplication to find the value of z. z = 60 * (4/3) z = 240/3 z = 80

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Math Problems

Grade 7

Solve two-step equations with parentheses

Full solution

Q. Solve for

z

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\frac{3}{4} z+8=68

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Answer:

z=

Subtract $8$ : Subtract $8$ from both sides of the equation to isolate the term containing $z$ . $\newline$ $\frac{3}{4}z + 8 - 8 = 68 - 8$ $\newline$ This simplifies to: $\newline$ $\frac{3}{4}z = 60$
Multiply by reciprocal: Multiply both sides of the equation by the reciprocal of $(\frac{3}{4})$ to solve for $z$ . The reciprocal of $(\frac{3}{4})$ is $(\frac{4}{3})$ . So we multiply both sides by $(\frac{4}{3})$ : $(\frac{4}{3}) \times (\frac{3}{4})z = 60 \times (\frac{4}{3})$ This simplifies to: $z = 60 \times (\frac{4}{3})$
Perform multiplication: Perform the multiplication to find the value of $z$ . $z = 60 \times (\frac{4}{3})$ $z = \frac{240}{3}$ $z = 80$