Solve for z. (2)/(3)z+5=55 Answer: z=

Subtract 5 to isolate z: Subtract 5 from both sides of the equation to isolate the term containing z. We start with the equation (2/3)z + 5 = 55 and subtract 5 from both sides to get (2/3)z = 50. Calculation: 55 - 5 = 50Multiply by reciprocal: Multiply both sides of the equation by the reciprocal of (2/3) to solve for z. The reciprocal of (2/3) is (3/2). We multiply both sides of the equation by (3/2) to isolate z. Calculation: (2/3)z * (3/2) = 50 * (3/2)Simplify equation: Simplify both sides of the equation. When we multiply (2/3)z by (3/2), the (2/3) and (3/2) cancel each other out, leaving us with z on the left side. On the right side, we multiply 50 by (3/2). Calculation: z = 50 * (3/2) = 50 * 1.5 = 75

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Solve for $z$ . $\newline$ $\frac{2}{3} z+5=55$ $\newline$ Answer: $z=$

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Math Problems

Grade 7

Solve two-step equations with parentheses

Full solution

Q. Solve for

z

\newline

\frac{2}{3} z+5=55

\newline

Answer:

z=

Subtract $5$ to isolate z: Subtract $5$ from both sides of the equation to isolate the term containing z. $\newline$ We start with the equation $(\frac{2}{3})z + 5 = 55$ and subtract $5$ from both sides to get $(\frac{2}{3})z = 50$ . $\newline$ Calculation: $55 - 5 = 50$
Multiply by reciprocal: Multiply both sides of the equation by the reciprocal of $(\frac{2}{3})$ to solve for $z$ . The reciprocal of $(\frac{2}{3})$ is $(\frac{3}{2})$ . We multiply both sides of the equation by $(\frac{3}{2})$ to isolate $z$ . Calculation: $(\frac{2}{3})z \times (\frac{3}{2}) = 50 \times (\frac{3}{2})$
Simplify equation: Simplify both sides of the equation. $\newline$ When we multiply $(\frac{2}{3})z$ by $(\frac{3}{2})$ , the $(\frac{2}{3})$ and $(\frac{3}{2})$ cancel each other out, leaving us with $z$ on the left side. On the right side, we multiply $50$ by $(\frac{3}{2})$ . $\newline$ Calculation: $z = 50 \times (\frac{3}{2}) = 50 \times 1.5 = 75$