Solve for y. 62=(2)/(3)y+16 Answer: y=

Isolate y term: Isolate the term containing y. To do this, we need to subtract 16 from both sides of the equation to get the term with y by itself on one side. 62 - 16 = (2/3)y + 16 - 16 46 = (2/3)ySolve for y: Solve for y. Now we need to multiply both sides of the equation by the reciprocal of (2/3), which is (3/2), to solve for y. (3/2) * 46 = y * (2/3) * (3/2) 69 = y

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Solve for $y$ . $\newline$ $62=\frac{2}{3} y+16$ $\newline$ Answer: $y=$

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Math Problems

Grade 6

Solve one-step equations with whole numbers

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Q. Solve for

y

\newline

62=\frac{2}{3} y+16

\newline

Answer:

y=

Isolate y term: Isolate the term containing y. $\newline$ To do this, we need to subtract $16$ from both sides of the equation to get the term with $y$ by itself on one side. $\newline$ $62 - 16 = \left(\frac{2}{3}\right)y + 16 - 16$ $\newline$ $$46$ = \left(\frac{$2$}{$3$}\right)y
Solve for y: Solve for y.$\newline$Now we need to multiply both sides of the equation by the reciprocal of $(\frac{2}{3})$, which is $(\frac{3}{2})$, to solve for y.$\newline$$(\frac{3}{2}) \times 46 = y \times (\frac{2}{3}) \times (\frac{3}{2})$$\newline$$69 = y$