Solve for x. (x+8)/(x-7)=(7)/(4) Answer:

Cross-multiply fractions: Cross-multiply to eliminate the fractions. Multiply both sides of the equation by (x-7) and 4 to get rid of the denominators. 4(x + 8) = 7(x - 7)Distribute numbers: Distribute the numbers on both sides. 4x + 32 = 7x - 49Combine like terms: Get all the x terms on one side and the constants on the other side. Subtract 4x from both sides to get the x terms on one side. 32 = 7x - 4x - 49Isolate x term: Combine like terms. 32 = 3x - 49Divide by 3: Add 49 to both sides to isolate the x term. 32 + 49 = 3x 81 = 3xDivide both sides by 3 to solve for x. 81 / 3 = x 27 = x

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Solve for
x.

(x+8)/(x-7)=(7)/(4)
Answer:

Solve for $\mathrm{x}$ . $\newline$ $\frac{x+8}{x-7}=\frac{7}{4}$ $\newline$ Answer:

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Math Problems

Grade 8

Solve equations with the distributive property

Full solution

Q. Solve for

\mathrm{x}

\newline

\frac{x+8}{x-7}=\frac{7}{4}

\newline

Answer:

Cross-multiply fractions: Cross-multiply to eliminate the fractions. $\newline$ Multiply both sides of the equation by $(x-7)$ and $4$ to get rid of the denominators. $\newline$ $4(x + 8) = 7(x - 7)$
Distribute numbers: Distribute the numbers on both sides. $4x + 32 = 7x - 49$
Combine like terms: Get all the $x$ terms on one side and the constants on the other side. $\newline$ Subtract $4x$ from both sides to get the $x$ terms on one side. $\newline$ $32 = 7x - 4x - 49$
Isolate x term: Combine like terms. $\newline$ $32 = 3x - 49$
Divide by $3$ : Add $49$ to both sides to isolate the $x$ term. $\newline$ $32 + 49 = 3x$ $\newline$ $81 = 3x$
Divide by $3$ : Add $49$ to both sides to isolate the $x$ term. $\newline$ $32 + 49 = 3x$ $\newline$ $81 = 3x$ Divide both sides by $3$ to solve for $x$ . $\newline$ $\frac{81}{3} = x$ $\newline$ $27 = x$