solve for x: x^^2+2x+1=0

Recognize quadratic equation: Recognize the equation x^2 + 2x + 1 = 0 as a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. Here, a = 1, b = 2, and c = 1.Identify factorability: Identify if the quadratic can be factored. The quadratic x^2 + 2x + 1 is a perfect square trinomial because it can be written as (x + 1)^2.Factor the equation: Factor the quadratic equation. x^2 + 2x + 1 = (x + 1)(x + 1) = (x + 1)^2Set equal to zero: Set the factored form equal to zero to find the solution(s). (x + 1)^2 = 0Solve for x: Solve for x by taking the square root of both sides. √((x + 1)^2) = √(0) x + 1 = 0Subtract to isolate x: Subtract 1 from both sides to isolate x. x = -1

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solve for $x$ : $\newline$ $x^2+2x+1=0$

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Grade 8

Solve two-step inequalities

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x^2+2x+1=0

Recognize quadratic equation: Recognize the equation $x^2 + 2x + 1 = 0$ as a quadratic equation. $\newline$ The general form of a quadratic equation is $ax^2 + bx + c = 0$ . Here, $a = 1$ , $b = 2$ , and $c = 1$ .
Identify factorability: Identify if the quadratic can be factored. $\newline$ The quadratic $x^2 + 2x + 1$ is a perfect square trinomial because it can be written as $(x + 1)^2$ .
Factor the equation: Factor the quadratic equation. $\newline$ $x^2 + 2x + 1 = (x + 1)(x + 1) = (x + 1)^2$
Set equal to zero: Set the factored form equal to zero to find the solution(s). $\newline$ $(x + 1)^2 = 0$
Solve for x: Solve for x by taking the square root of both sides. $\newline$ $\sqrt{(x + 1)^2} = \sqrt{0}$ $\newline$ $x + 1 = 0$
Subtract to isolate $x$ : Subtract $1$ from both sides to isolate $x$ . $\newline$ $x = -1$