Solve for x : sqrt(2x+26)-10=-4 Answer:

Isolate square root: First, isolate the square root on one side of the equation by adding 10 to both sides. sqrt(2x+26) - 10 + 10 = -4 + 10 This simplifies to: sqrt(2x+26) = 6Square both sides: Next, square both sides of the equation to eliminate the square root. (sqrt(2x+26))^2 = 6^2 This results in: 2x + 26 = 36Subtract and solve: Now, subtract 26 from both sides to solve for 2x. 2x + 26 - 26 = 36 - 26 This simplifies to: 2x = 10Divide and find x: Finally, divide both sides by 2 to solve for x. 2x / 2 = 10 / 2 This gives us: x = 5

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Solve for
x :

sqrt(2x+26)-10=-4
Answer:

Solve for $\mathrm{x}$ : $\newline$ $\sqrt{2 x+26}-10=-4$ $\newline$ Answer:

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Math Problems

Grade 8

Relationship between squares and square roots

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Q. Solve for

\mathrm{x}

\newline

\sqrt{2 x+26}-10=-4

\newline

Answer:

Isolate square root: First, isolate the square root on one side of the equation by adding $10$ to both sides. $\newline$ $\sqrt{2x+26} - 10 + 10 = -4 + 10$ $\newline$ This simplifies to: $\newline$ $\sqrt{2x+26} = 6$
Square both sides: Next, square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{2x+26})^2 = 6^2$ $\newline$ This results in: $\newline$ $2x + 26 = 36$
Subtract and solve: Now, subtract $26$ from both sides to solve for $2x$ . $\newline$ $2x + 26 - 26 = 36 - 26$ $\newline$ This simplifies to: $\newline$ $2x = 10$
Divide and find x: Finally, divide both sides by $2$ to solve for $x$ . $\newline$ $\frac{2x}{2} = \frac{10}{2}$ $\newline$ This gives us: $\newline$ $x = 5$