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Solve for 
x, rounding to the nearest hundredth.

2^(x)=7
Answer:

Solve for x x , rounding to the nearest hundredth.\newline2x=7 2^{x}=7 \newlineAnswer:

Full solution

Q. Solve for x x , rounding to the nearest hundredth.\newline2x=7 2^{x}=7 \newlineAnswer:
  1. Apply Logarithm: Apply the logarithm to both sides of the equation 2x=72^x = 7.\newlinelog(2x)=log(7)\log(2^x) = \log(7)
  2. Use Power Property: Use the power property of logarithms to bring the exponent xx in front of the log.\newlinexlog(2)=log(7)x \cdot \log(2) = \log(7)
  3. Isolate xx: Isolate xx by dividing both sides of the equation by log(2)\log(2).\newlinex=log(7)log(2)x = \frac{\log(7)}{\log(2)}
  4. Calculate xx: Calculate the value of xx using a calculator.x=log(7)log(2)x = \frac{\log(7)}{\log(2)}x=2.807354922057604107x = 2.807354922057604107\ldots
  5. Round to Nearest Hundredth: Round the calculated value of xx to the nearest hundredth.x2.81x \approx 2.81

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