Solve for x. Enter the solutions from least to greatest. 6x^(2)-18 x-240=0 lesser x= greater x=

Simplify Equation: Simplify the equation by dividing all terms by 6 to make calculations easier. 6x^2 - 18x - 240 = 0 => x^2 - 3x - 40 = 0 Factorize Quadratic: Factorize the quadratic equation x^2 - 3x - 40. Looking for two numbers that multiply to -40 and add to -3. These numbers are -8 and 5. => (x - 8)(x + 5) = 0 Solve for x: Solve each factor set to zero to find the values of x. x - 8 = 0 => x = 8 x + 5 = 0 => x = -5

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Solve for $x$ . Enter the solutions from least to greatest. $\newline$ $6x^{2}-18x-240=0$ $\newline$ lesser $x=$ $\newline$ greater $x=$

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Precalculus

Find the roots of factored polynomials

Full solution

Q. Solve for

x

. Enter the solutions from least to greatest.

\newline

6x^{2}-18x-240=0

\newline

lesser

x=

\newline

greater

x=

Simplify Equation: Simplify the equation by dividing all terms by $6$ to make calculations easier. $\newline$ $6x^2 - 18x - 240 = 0$ $\newline$ $\Rightarrow x^2 - 3x - 40 = 0$
Factorize Quadratic: Factorize the quadratic equation $x^2 - 3x - 40$ . $\newline$ Looking for two numbers that multiply to $-40$ and add to $-3$ . These numbers are $-8$ and $5$ . $\newline$ => $(x - 8)(x + 5) = 0$
Solve for x: Solve each factor set to zero to find the values of $x$ . $x - 8 = 0 \Rightarrow x = 8$ $x + 5 = 0 \Rightarrow x = -5$