Solve for x. Enter the solutions from least to greatest. (2x+4)(3x-2)=0 lesser x= greater x=

Set First Factor Equal: We set each factor equal to zero and solve for x. First, set the first factor equal to zero: 2x + 4 = 0. Subtract 4 from both sides to isolate the term with x: 2x = -4. Divide both sides by 2 to solve for x: x = -4 / 2. Simplify the fraction to find the first solution: x = -2.Solve for First Solution: Now, set the second factor equal to zero: 3x - 2 = 0. Add 2 to both sides to isolate the term with x: 3x = 2. Divide both sides by 3 to solve for x: x = 2 / 3. This gives us the second solution.Set Second Factor Equal: We have found two solutions for x: x = -2 and x = 2/3. To enter the solutions from least to greatest, we compare the values. Since -2 is less than 2/3, the lesser value is x = -2 and the greater value is x = 2/3.

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Math Problems

Algebra 1

Multiply polynomials

Full solution

Q. Solve for

x

. Enter the solutions from least to greatest.

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(2x+4)(3x-2)=0

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lesser

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x=

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greater

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x=

Set First Factor Equal: We set each factor equal to zero and solve for $x$ . First, set the first factor equal to zero: $2x + 4 = 0$ . Subtract $4$ from both sides to isolate the term with $x$ : $2x = -4$ . Divide both sides by $2$ to solve for $x$ : $x = -4 / 2$ . Simplify the fraction to find the first solution: $x = -2$ .
Solve for First Solution: Now, set the second factor equal to zero: $3x - 2 = 0$ . Add $2$ to both sides to isolate the term with $x$ : $3x = 2$ . Divide both sides by $3$ to solve for $x$ : $x = \frac{2}{3}$ . This gives us the second solution.
Set Second Factor Equal: We have found two solutions for $x$ : $x = -2$ and $x = \frac{2}{3}$ . To enter the solutions from least to greatest, we compare the values. Since $-2$ is less than $\frac{2}{3}$ , the lesser value is $x = -2$ and the greater value is $x = \frac{2}{3}$ .