Solve for x and write your answer in simplest form. 3(4x-(1)/(5))-4x=6(x+(3)/(5)) Answer: x=

Distribute 3: Distribute the 3 into the parentheses on the left side of the equation. 3(4x) - 3(1/5) = 12x - 3/5Distribute 6: Distribute the 6 into the parentheses on the right side of the equation. 6(x) + 6(3/5) = 6x + 18/5Combine like terms: Combine like terms on both sides of the equation. 12x - 3/5 - 4x = 6x + 18/5Subtract 6x: Subtract 6x from both sides to get all x terms on one side. 12x - 4x - 6x = 18/5 + 3/5Combine x terms: Combine the x terms and the constant terms. 2x = 21/5Divide by 2: Divide both sides by 2 to solve for x. x = (21/5) / 2Simplify right side: Simplify the right side by dividing 21 by 5 and then by 2. x = 21/5 * 1/2 x = 21/10 x = 2.1

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Math Problems

Precalculus

Find the roots of factored polynomials

Full solution

Q. Solve for

x

and write your answer in simplest form.

\newline

3\left(4 x-\frac{1}{5}\right)-4 x=6\left(x+\frac{3}{5}\right)

\newline

Answer:

x=

Distribute $3$ : Distribute the $3$ into the parentheses on the left side of the equation. $3(4x) - 3\left(\frac{1}{5}\right) = 12x - \frac{3}{5}$
Distribute $6$ : Distribute the $6$ into the parentheses on the right side of the equation. $6(x) + 6\left(\frac{3}{5}\right) = 6x + \frac{18}{5}$
Combine like terms: Combine like terms on both sides of the equation. $\newline$ $12x - \frac{3}{5} - 4x = 6x + \frac{18}{5}$
Subtract $6x$ : Subtract $6x$ from both sides to get all $x$ terms on one side. $\newline$ $12x - 4x - 6x = \frac{18}{5} + \frac{3}{5}$
Combine $x$ terms: Combine the $x$ terms and the constant terms. $2x = \frac{21}{5}$
Divide by $2$ : Divide both sides by $2$ to solve for $x$ . $x = \frac{21}{5} / 2$
Simplify right side: Simplify the right side by dividing $21$ by $5$ and then by $2$ . $\newline$ $x = \frac{21}{5} \times \frac{1}{2}$ $\newline$ $x = \frac{21}{10}$ $\newline$ $x = $2$.$1$