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Solve for 
x.

2(x-1)+x+5=-27
Answer:

Solve for x \mathrm{x} .\newline2(x1)+x+5=27 2(x-1)+x+5=-27 \newlineAnswer:

Full solution

Q. Solve for x \mathrm{x} .\newline2(x1)+x+5=27 2(x-1)+x+5=-27 \newlineAnswer:
  1. Distribute 22 into parentheses: Distribute the 22 into the parentheses.\newlineWe need to apply the distributive property to the expression 2(x1)2(x-1). This means we multiply 22 by both xx and 1-1.\newline2(x1)=2×x2×1=2x22(x-1) = 2\times x - 2\times 1 = 2x - 2
  2. Combine like terms: Combine like terms on the left side of the equation.\newlineAfter distributing, we have 2x2+x+52x - 2 + x + 5. We combine the xx terms and the constant terms.\newline2x+x=3x2x + x = 3x\newline2+5=3-2 + 5 = 3\newlineSo, the equation now is 3x+3=273x + 3 = -27.
  3. Subtract 33 from both sides: Subtract 33 from both sides of the equation to isolate the term with xx. We want to get xx by itself, so we need to remove the constant term from the left side. 3x+33=2733x + 3 - 3 = -27 - 3 This simplifies to 3x=303x = -30.
  4. Divide both sides: Divide both sides of the equation by 33 to solve for xx.\newlineTo isolate xx, we divide both sides of the equation by 33.\newline3x3=303\frac{3x}{3} = \frac{-30}{3}\newlineThis simplifies to x=10x = -10.