Q. Solve for the exact value of x.log6(4x)+log6(9)=3Answer:
Apply product rule of logarithms: Apply the product rule of logarithms to combine the two logarithmic terms.The product rule of logarithms states that logb(m)+logb(n)=logb(m∗n).Therefore, log6(4x)+log6(9) becomes log6(4x⋅9).
Simplify expression: Simplify the expression inside the logarithm.Multiplying 4x by 9 gives us 36x.So, log6(4x×9) simplifies to log6(36x).
Set equal to 3: Set the simplified logarithmic expression equal to 3. We now have the equation log6(36x)=3.
Convert to exponential form: Convert the logarithmic equation to its exponential form.The exponential form of logb(a)=c is bc=a.So, 63=36x.
Calculate value of 63: Calculate the value of 63.63 equals 216.So, we have 216=36x.
Solve for x: Solve for x by dividing both sides of the equation by 36.Dividing 216 by 36 gives us x=36216.
Calculate exact value of x: Calculate the exact value of x. 216 divided by 36 equals 6. So, x=6.
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