Solve for the exact value of x. 4ln(6x+10)-9=23 Answer:

Add 9 to isolate: Isolate the logarithmic expression by adding 9 to both sides of the equation. 4ln(6x+10) - 9 + 9 = 23 + 9 4ln(6x+10) = 32Divide by 4: Divide both sides of the equation by 4 to solve for the logarithmic part. (4ln(6x+10))/4 = 32/4 ln(6x+10) = 8Exponentiate to remove ln: Exponentiate both sides of the equation to remove the natural logarithm, using the property e^(ln(x)) = x. e^(ln(6x+10)) = e^8 6x + 10 = e^8Subtract 10 to isolate: Subtract 10 from both sides of the equation to isolate the term with x. 6x + 10 - 10 = e^8 - 10 6x = e^8 - 10Divide by 6: Divide both sides of the equation by 6 to solve for x. 6x/6 = (e^8 - 10)/6 x = (e^8 - 10)/6

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Solve for the exact value of
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4ln(6x+10)-9=23
Answer:

Solve for the exact value of $x$ . $\newline$ $4 \ln (6 x+10)-9=23$ $\newline$ Answer:

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Q. Solve for the exact value of

x

\newline

4 \ln (6 x+10)-9=23

\newline

Answer:

Add $9$ to isolate: Isolate the logarithmic expression by adding $9$ to both sides of the equation. $\newline$ $4\ln(6x+10) - 9 + 9 = 23 + 9$ $\newline$ $4\ln(6x+10) = 32$
Divide by $4$ : Divide both sides of the equation by $4$ to solve for the logarithmic part. $\newline$ $(4\ln(6x+10))/4 = 32/4$ $\newline$ $\ln(6x+10) = 8$
Exponentiate to remove ln: Exponentiate both sides of the equation to remove the natural logarithm, using the property $e^{\ln(x)} = x$ . $\newline$ $e^{\ln(6x+10)} = e^8$ $\newline$ $6x + 10 = e^8$
Subtract $10$ to isolate: Subtract $10$ from both sides of the equation to isolate the term with $x$ . $6x + 10 - 10 = e^{8} - 10$ $6x = e^{8} - 10$
Divide by $6$ : Divide both sides of the equation by $6$ to solve for $x$ . $\frac{6x}{6} = \frac{e^8 - 10}{6}$ $x = \frac{e^8 - 10}{6}$