Solve for the exact value of x. 2ln(8x-8)-6=-10 Answer:

Isolate natural logarithm term: Isolate the natural logarithm term. We start by adding 6 to both sides of the equation to isolate the natural logarithm term. 2ln(8x-8) - 6 + 6 = -10 + 6 2ln(8x-8) = -4Divide to solve logarithm: Divide both sides by 2 to solve for the natural logarithm of the expression. 2ln(8x-8) / 2 = -4 / 2 ln(8x-8) = -2Exponentiate to remove logarithm: Exponentiate both sides to remove the natural logarithm. We raise e to the power of both sides of the equation to remove the natural logarithm. e^(ln(8x-8)) = e^(-2) 8x - 8 = e^(-2)Solve for x: Solve for x. We add 8 to both sides and then divide by 8 to solve for x. 8x - 8 + 8 = e^(-2) + 8 8x = e^(-2) + 8 x = (e^(-2) + 8) / 8

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Solve for the exact value of
x.

2ln(8x-8)-6=-10
Answer:

Solve for the exact value of $x$ . $\newline$ $2 \ln (8 x-8)-6=-10$ $\newline$ Answer:

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Q. Solve for the exact value of

x

\newline

2 \ln (8 x-8)-6=-10

\newline

Answer:

Isolate natural logarithm term: Isolate the natural logarithm term. $\newline$ We start by adding $6$ to both sides of the equation to isolate the natural logarithm term. $\newline$ $2\ln(8x-8) - 6 + 6 = -10 + 6$ $\newline$ $2\ln(8x-8) = -4$
Divide to solve logarithm: Divide both sides by $2$ to solve for the natural logarithm of the expression. $\frac{2\ln(8x-8)}{2} = \frac{-4}{2}$ $\ln(8x-8) = -2$
Exponentiate to remove logarithm: Exponentiate both sides to remove the natural logarithm. $\newline$ We raise $e$ to the power of both sides of the equation to remove the natural logarithm. $\newline$ $e^{\ln(8x-8)} = e^{-2}$ $\newline$ $8x - 8 = e^{-2}$
Solve for x: Solve for x. $\newline$ We add $8$ to both sides and then divide by $8$ to solve for $x$ . $\newline$ $8x - 8 + 8 = e^{-2} + 8$ $\newline$ $8x = e^{-2} + 8$ $\newline$ $x = \frac{e^{-2} + 8}{8}$